Степени и корни

an =

a ⋅ a ⋅ a ⋅ ... ⋅ a ⋅ a ⋅ a


n раз

an =

a ⋅ a ⋅ a ⋅ ... ⋅ a ⋅ a ⋅ a

n раз

a ∈ R, b ∈ R, b ≠ 0, m ∈ Z, n ∈ Z

Свойства степеней

1) a0 = 1

2) a1 = a

3) 1n = 1

4) anam = an + m

5) an am = an−m

6) (ab)n = anbn

7) ( a b ) n = an bn

8) (an)m = anm

9) a−n= 1 an

10) ( a b ) −n = ( b a ) n

Свойства корней

1) ann=a

2) a n m = an m

3) ( a m ) n = an m

4) a m n = a nm

5) akm kn = an m

6) ab n = a n ⋅ b n

7) a b n = an bn

8) am bn= anbmmn

Решение показательных неравенств:

f(x)g1(x) − f(x)g2(x) > 0 =>

(f(x) − 1)(g1(x) − g2(x)) > 0

(ab − ac ≤ 0 => (a − 1)(b − c) ≤ 0)

Вверх